Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set: 9

Answer

$4\sqrt{2}\approx 5.66$ units

Work Step by Step

RECALL: The distance between the points $(x_1, y_1)$ and $(x_2, y_2)$ can be found using the distance formula $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ Use the formula above to obtain: $d=\sqrt{(0-4)^2+(-3-1)^2} \\d=\sqrt{(-4)^2+(-4)^2} \\d=\sqrt{16+16} \\d=\sqrt{32} \\d=\sqrt{16(2)} \\d=\sqrt{4^2(2)} \\d=4\sqrt{2} \\d \approx 5.66$
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