Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 765: 15

Answer

$\sqrt{93}$

Work Step by Step

The distance formula from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$. Hence here: $d=\sqrt{(3\sqrt3-(-\sqrt3))^2+(\sqrt5-4\sqrt5))^2}=\sqrt{(4\sqrt3)^2+(-3\sqrt5)^2}=\sqrt{48+45}=\sqrt{93}$
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