Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 765: 8


$2\sqrt{10} \approx 6.32$ units

Work Step by Step

RECALL: The distance between the points $(x_1, y_1)$ and $(x_2, y_2)$ can be found using the distance formula $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ Use the formula above to obtain: $d=\sqrt{-4-2)^2+[-1-(-3)]^2} \\d=\sqrt{(-6)^2+(-1+3)^2} \\d=\sqrt{36+2^2} \\d=\sqrt{36+4} \\d=\sqrt{40} \\d=\sqrt{4(10)} \\d=\sqrt{2^2(10} \\d=2\sqrt{10} \\d \approx 6.32$
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