Answer
$(x-2)^2+(y+1)^2=4$
Work Step by Step
RECALL:
The standard form of the equation of a circle with a center at $(h, k)$ and a radius of $r$ units is:
$(x-h)^2+(y-k)^2=r^2$
The given circle has its center at $(2, -1)$.
The point on the circle that is directly to the left of the center is $(0, -1)$.
This point is 2 units away from the center.
This means that the radius is 2 units.
Since the center is at (2, -1), we know that h=2 and k = -1.
The radius is 2 units, so r = 2.
Therefore, the equation of the given circle is:
$(x-2)^2 + [(y-(-1)]^2=2^2
\\(x-2)^2+(y+1)^2=4$
