#### Answer

center: $(3, 1)$
radius = $6$ units
Refer to the image below for the graph.

#### Work Step by Step

RECALL:
The standard form of the equation of a circle with a center at $(h, k)$ and a radius of $r$ units is:
$(x-h)^2+(y-k)^2=r^2$
The given equation can be written as $(x-3)^2+(y-1)^2=6^2$.
This is the same form as the standard equation above, so its center must be at the point $(3,1)$ and its radius must be 6.
Thus, the circle has:
center: $(3, 1)$
radius = $6$ units
To graph the equation, do the following steps:
(1) Plot the center $(3, 1)$, and then locate the points 6 units to the left, to the right, above, and below the circle's center.
These points are:
$(9, 1)$
$(-3, 1)$
$(3, 7)$
$(3, -5)$
(ii) Connect the four points (excluding the center) together using a curve to form a circle.
(Please refer to the attached image in the answer part above.)