#### Answer

center: $(2, 3)$
radius = $4$ units
Refer to the image below for the graph.

#### Work Step by Step

RECALL:
The standard form of the equation of a circle with a center at $(h, k)$ and a radius of $r$ units is:
$(x-h)^2+(y-k)^2=r^2$
The given equation can be written as $(x-2)^2+(y-3)^2=4^2$.
This is the same form as the standard equation above, so its center must be at the point $(2,3)$ and its radius must be 4.
Thus, the circle has:
center: $(2, 3)$
radius = $4$ units
To graph the equation, do the following steps:
(1) Plot the center $(2, 3)$, and then locate the points 4 units to the left, to the right, above, and below the circle's center.
These points are:
$(2,7)$
$(2,-1)$
$(6,3)$
$(-2, 3)$
(ii) Connect the four points (excluding the center) together using a curve to form a circle.
(Please refer to the attached image in the answer part above.)