Answer
$\sqrt{5}$
Work Step by Step
The distance formula from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$.
Hence here: $d=\sqrt{(\frac{7}{3}-\frac{1}{3})^2+(\frac{1}{5}-\frac{6}{5})^2}=\sqrt{(2)^2+(-1)^2}=\sqrt{4+1}=\sqrt{5}$
