## Intermediate Algebra for College Students (7th Edition)

$(5\sqrt3, -4)$
RECALL: The midpoint of $(x_1, y_1)$ and $(x_2, y_2)$ can be found using the midpoint formula $\text{midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$ Use the formula above to obtain: $\text{midpoint} \\=\left(\dfrac{7\sqrt3+3\sqrt3}{2}, \dfrac{-6+(-2)}{2}\right) \\=\left(\dfrac{10\sqrt3}{2}, \dfrac{-8}{2}\right) \\=(5\sqrt3, -4)$