Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set: 34

Answer

$(x-2)^2+(y+1)^2=16$

Work Step by Step

RECALL: The standard form of the equation of a circle with a center of $(h, k)$ and a radius of $r$ units is: $(x-h)^2 + (y-k)^2 = r^2$ Use the standard form above where $h=2$, $k=-1$, and $r=4$ to obtain: $(x-2)^2 + [y-(-1)^2] =4^2 \\(x-2)^2+(y+1)^2=16$
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