Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set: 19

Answer

$(4, 6)$

Work Step by Step

RECALL: The midpoint of $(x_1, y_1)$ and $(x_2, y_2)$ can be found using the midpoint formula $\text{midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$ Use the formula above to obtain: $\text{midpoint}=\left(\frac{6+2}{2}, \frac{8+4}{2}\right)=\left(\frac{8}{2}, \frac{12}{2}\right)=(4, 6)$
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