Answer
$\\(x+1)^2+(y-4)^2=4$
Work Step by Step
RECALL:
The standard form of the equation of a circle with a center of $(h, k)$ and a radius of $r$ units is:
$(x-h)^2 + (y-k)^2 = r^2$
The given circle has its center at $(-1, 4)$ and a radius of 2 units.
Use the standard form above where $h=-1$, $k=4$, and $r=2$ to obtain:
$[x-(-1)]^2 + (y-4)^2 =2^2
\\(x+1)^2+(y-4)^2=4$
