Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 765: 62



Work Step by Step

RECALL: The standard form of the equation of a circle with a center at $(h, k)$ and a radius of $r$ units is: $(x-h)^2+(y-k)^2=r^2$ The given circle has its center at $(3, -1)$. The point on the circle that is directly to the left of the center is $(0, -1)$. This point is 3 units away from the center. This means that the radius is 3 units. Since the center is at (3, -1), we know that h=3 and k = -1. The radius is 3 units so r = 3. Therefore, the equation of the given circle is: $(x-3)^2 + [(y-(-1)]^2=3^2 \\(x-3)^2+(y+1)^2=9$
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