Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set: 25

Answer

$(-3, -2)$

Work Step by Step

RECALL: The midpoint of $(x_1, y_1)$ and $(x_2, y_2)$ can be found using the midpoint formula $\text{midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$ Use the formula above to obtain: $\text{midpoint} \\=\left(\dfrac{-\frac{7}{2}+(-\frac{5}{2})}{2}, \dfrac{\frac{3}{2}+(-\frac{11}{2})}{2}\right) \\=\left(\dfrac{-\frac{12}{2}}{2}, \frac{-\frac{8}{2}}{2}\right) \\=(-\frac{6}{2}, -\frac{4}{2}) \\=(-3, -2)$
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