Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.1 - Distance and Midpoint Formulas; Circles - Exercise Set: 39

Answer

$\\(x+4)^2+y^2=100$

Work Step by Step

RECALL: The standard form of the equation of a circle with a center of $(h, k)$ and a radius of $r$ units is: $(x-h)^2 + (y-k)^2 = r^2$ The given circle has its center at $(-4, 0)$ and a radius of $10$ units. Use the standard form above where $h=-4$, $k=0$, and $r=10$ to obtain: $[x-(-4)]^2 + (y-0)^2 =10^2 \\(x+4)^2+y^2=100$
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