Answer
$k=-\frac{1}{15}\ln 10000\approx-0.614023$
Work Step by Step
We solve for $k$:
$e^{-15k}=10000$
$\ln e^{-15k}=\ln 10000$
$-15k=\ln 10000$
$k=-\frac{1}{15}\ln 10000\approx-0.614023$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check - Page 425: 74
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
