College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check: 38

Answer

$49$

Work Step by Step

RECALL: (1) $e^{\ln{x}}=x$ (2) $n \cdot \ln{x} = \ln{(x^n)}$ Use rule (2) above to obtain: $e^{2\ln{7}}=e^{\ln{(7^2)}}$ Use rule (2) above with $x=7^2$ to obtain: $e^{\ln{(7^2)}}=7^2=49$ Thus, $e^{2\ln{7}}=49$
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