## College Algebra 7th Edition

Published by Brooks Cole

# Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check - Page 425: 38

#### Answer

$49$

#### Work Step by Step

RECALL: (1) $e^{\ln{x}}=x$ (2) $n \cdot \ln{x} = \ln{(x^n)}$ Use rule (2) above to obtain: $e^{2\ln{7}}=e^{\ln{(7^2)}}$ Use rule (2) above with $x=7^2$ to obtain: $e^{\ln{(7^2)}}=7^2=49$ Thus, $e^{2\ln{7}}=49$

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