College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check - Page 425: 29


$\log_2{128} = 7$

Work Step by Step

Note that $128=2^7$. Thus, the given expression is equivalent to: $=\log_2{(2^7)}$ RECALL: For any real number $a \gt 0, a \ne1$, and any integer $n$: $\log_a{(a^n)} = n$ Use the rule above to obtain: $\log_2{(2^7)} = 7$ Thus, $\log_2{128} = 7$
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