## College Algebra 7th Edition

$\log_2{128} = 7$
Note that $128=2^7$. Thus, the given expression is equivalent to: $=\log_2{(2^7)}$ RECALL: For any real number $a \gt 0, a \ne1$, and any integer $n$: $\log_a{(a^n)} = n$ Use the rule above to obtain: $\log_2{(2^7)} = 7$ Thus, $\log_2{128} = 7$