## College Algebra 7th Edition

$2$
RECALL: $\log{(10^x)}=x$ Use the rule above to obtain: $\log{(\log{10^{100})}}=\log{100}$ Note that $100=10^2$. Thus, $\log{100}=\log{(10^2)}$ Use the rule in the recall part above to obtain: $\log{(10^2)} = 2$