## College Algebra 7th Edition

Published by Brooks Cole

# Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check - Page 425: 44

#### Answer

$2$

#### Work Step by Step

RECALL: $\log{(10^x)}=x$ Use the rule above to obtain: $\log{(\log{10^{100})}}=\log{100}$ Note that $100=10^2$. Thus, $\log{100}=\log{(10^2)}$ Use the rule in the recall part above to obtain: $\log{(10^2)} = 2$

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