Answer
$x=3$
Work Step by Step
We solve:
$\log_{8}(x+5)-\log_{8}(x-2)=1$
$\log_{8}\frac{x+5}{x-2}=1$
$8^1=\frac{x+5}{x-2}$
$x+5=8(x-2)$
$x+5=8x-16$
$7x=21 $
$x=3$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check - Page 425: 70
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