College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check - Page 425: 37


$\log_5{\sqrt5} = \frac{1}{2}$

Work Step by Step

Use the rule $\sqrt{a} = a^{\frac{1}{2}}$ to obtain: $\log_5{\sqrt5} = \log_5{(5^{\frac{1}{2}})}$ Use the rule $\log_a{(a^n)} = n$ to obtain: $\log_5{(5^{\frac{1}{2}})}=\frac{1}{2}$ Thus, $\log_5{\sqrt5} = \frac{1}{2}$
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