College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check: 51

Answer

$\log{96}$

Work Step by Step

RECALL: (1) $\log_a{(P^n)}=n \cdot \log_a{P}$ (2) $\log_a{(PQ)}= \log_a{P} + \log_a{Q}$ (3) $\log_a{(\frac{P}{Q})}= \log_a{P} - \log_a{Q}$ Use rule (1) above to obtain $\log{6}+4\log{2} \\= \log{6} + \log{(2^4)} \\=\log{6} + \log{16}$ Use rule (2) above to obtain: $\log{6} + \log{16} \\= \log{(6\cdot 16)} \\=\log{96}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.