Answer
$x=9$
Work Step by Step
We solve:
$\log_{3}(x-8)+\log_{3}x=2$
$\log_{3}((x-8)*x)=2$
$\log_{3}(x^2-8x)=2$
$3^2=x^2-8x$
$ x^{2}-8x-9=0$
$(x-9)(x+1)=0$
$(x-9)=0$ or $(x+1)=0$
$x=9$ or $x=-1$
However, $x=-1$ is not allowed in the original equation because we can't take the log of a negative number (undefined). So we throw this solution out.