Answer
$x \approx 1.58$
Work Step by Step
Take the common log of both sides to obtain:
$\log{(10^{6-3x})} = \log{18}$
Use the rule $\log{(a^n)} = n\cdot\log{a}$ to obtain:
$(6-3x)\log{10} = \log{18}$
Divide $\log{10}$ to both sides of the equation to obtain:
$\dfrac{(6-3x)\log{10}}{\log{10}} = \dfrac{\log{18}}{\log{10}}
\\6-3x=\dfrac{\log{18}}{\log{10}}$
Subtract $6$ on both sides of the equation to obtain:
$-3x=\dfrac{\log{18}}{\log{10}}-6$
Divide $-3$ on both of the equation to obtain:
$x = \dfrac{\frac{\log{18}}{\log{10}}-6}{-3}$
Use a calculator to obtain:
$x \approx 1.58$
