Answer
$\log_{49}{(\frac{1}{7})}=-\frac{1}{2}$
Work Step by Step
RECALL:
$a^y=x \longrightarrow \log_a{x}=y$
Use the rule above to obtain:
$49^{-\frac{1}{2}}=\frac{1}{7} \longrightarrow \log_{49}{(\frac{1}{7})}=-\frac{1}{2}$
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