College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check - Page 425: 72


$x=\frac{1}{3}(5+\frac{\log 7}{\log 2})\approx 2.602452$

Work Step by Step

$2^{3x-5}=7$ $(3x-5) \log 2 = \log 7$ $3x\log2-5\log2=\log7$ $3x\log2=5\log2+\log7$ $x=\frac{5\log2+\log7}{3\log 2}$ $x=\frac{1}{3}(5+\frac{\log 7}{\log 2})\approx 2.602452$
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