## College Algebra 7th Edition

$3$
Use the rule "$\log_a{P} - \log_a{Q} = \log_a{\left(\frac{P}{Q}\right)}$" to obtain: $=\log_5{\left(\frac{250}{2}\right)} \\=\log_5{\left(125\right)}$ Note that $125=5^3$. Thus, the expression above is equivalent to: $=\log_5{(5^3)}$ RECALL: $\log_a{(a^x)} = x$ Use the rule above to obtain: $\log_5{(5^3)} = 3$