## College Algebra (6th Edition)

The solutions are $x=-60$ and $x=68$
$(x-4)^{2/3}=16$ Raise both sides to $\dfrac{3}{2}$: $[(x-4)^{2/3}]^{3/2}=16^{3/2}$ $x-4=\sqrt{16^{3}}$ Simplify the right side: $x-4=\pm\sqrt{4096}$ $x-4=\pm64$ Solve for $x$: $x=4\pm64$ The solutions are: $x=4+64=68$ $x=4-64=-60$