College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 11



Work Step by Step

Square both sides and put all terms on one side to create a quadratic equation. Then use trial and error to factor it, and set the values found equal to zero. One of the solutions does not work. $\sqrt {3x+18}=x$ $(\sqrt {3x+18})^2=x^2$ $3x+18=x^2$ $x^2-3x-18=0$ $(x+3)(x-6)=0$ $x=-3,6$ $\sqrt {3\times-3+18}\ne-3$ $x=6$
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