College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 21



Work Step by Step

Isolate the square root on one side. Then square both sides and put all terms on one side. Factor by trial and error to solve for $x$. One of the answers does not work. $\sqrt {3x}+10=x+4$ $\sqrt {3x}=x-6$ $(\sqrt {3x})^2=(x-6)^2$ $3x=x^2-12x+36$ $x^2-15x+36=0$ $(x-3)(x-12)=0$ $x=3,12$ $\sqrt {3\times3}+10\ne3+4$ $x=12$
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