Answer
The solution is $x=13$
Work Step by Step
$(x-4)^{3/2}=27$
Raise both sides of the equation to $\dfrac{2}{3}$:
$[(x-4)^{3/2}]^{2/3}=27^{2/3}$
$x-4=\sqrt[3]{27^{2}}$
$x-4=9$
Solve for $x$:
$x=9+4$
$x=13$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 33
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