College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 20



Work Step by Step

Isolate the square root on one side. Then square both sides and put all terms on one side. Factor by trial and error to solve for $x$. One of the answers does not work. $\sqrt {2x+15}-6=x$ $(\sqrt {2x+15})^2=(x+6)^2$ $2x+15=x^2+12x+36$ $x^2+10x+21=0$ $(x+7)(x+3)=0$ $x=-7,-3$ $\sqrt {2\times-7+15}-6\ne-7$ $x=-3$
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