## College Algebra (6th Edition)

$x=4$
Separate the square roots on two sides. Then square both sides and combine like terms. When down to the last square root, square both sides again to solve. $\sqrt {x+5}-\sqrt {x-3}=2$ $\sqrt {x+5}=2+\sqrt {x-3}$ $(\sqrt {x+5})^2=(2+\sqrt {x-3})^2$ $x+5=4+4\sqrt {x-3}+x-3$ $4=4\sqrt {x-3}$ $\sqrt {x-3}=1$ $x=4$