## College Algebra (6th Edition)

$x=-2,0,2$
First, set the terms in the parentheses equal to zero, and do the same with $5x^{2}$. Then solve for each and include each solution in the final answer. $5x^{2}(x^{2}-4)=0$ $x^{2}-4=0$ $x=±2$ $5x^{2}=0$ $x=0$ $x=-2,0,2$