College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 3

Answer

x=-2, 2, or -$\frac{2}{3}$

Work Step by Step

3x$^3$+2x$^2$-12x-8=0 x$^2$(3x+2)-4(3x+2)=0 (x$^2$-4)(3x+2)=0 (x+2)(x-2)(3x+2)=0 x=-2, 2, or -$\frac{2}{3}$
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