College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 23

Answer

$x=8$

Work Step by Step

Separate the square roots on two sides. Then square both sides and combine like terms. When down to the last square root, square both sides again to solve. $\sqrt {x+8}-\sqrt {x-4}=2$ $\sqrt {x+8}=2+\sqrt {x-4}$ $(\sqrt {x+8})^2=(2+\sqrt {x-4})^2$ $x+8=4+4\sqrt {x-4}+x-4$ $8=4\sqrt {x-4}$ $\sqrt {x-4}=2$ $x=8$
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