College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 1



Work Step by Step

First, set the terms in the parentheses equal to zero, and do the same with $3x^{2}$. Then solve for each and include each solution in the final answer. $3x^{2}(x^{2}-16)=0$ $x^{2}-16=0$ $x=±4$ $3x^{2}=0$ $x=0$ $x=-4,0,4$
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