College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 19



Work Step by Step

Isolate the square root on one side. Then square both sides and put all terms on one side. Factor by trial and error to solve for $x$. One of the answers does not work. $\sqrt {2x+19}-8=x$ $\sqrt {2x+19}=x+8$ $(\sqrt {2x+19})^2=(x+8)^2$ $x^2+16x+64=2x+19$ $x^2+14x+45=0$ $(x+5)(x+9)=0$ $x=-9,-5$ $\sqrt {2\times-9+19}-8\ne-9$ $x=-5$
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