College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 16



Work Step by Step

Square both sides and put all terms on one side. Divide both sides by $x$. One of the answers does not work. $\sqrt {6x+1}=x-1$ $(\sqrt {6x+11})^2=(x-1)^2$ $6x+1=x^2-2x+1$ $x^2-8x=0$ $x^2=8x$ $x=0,8$ $\sqrt{6\times0+1}\ne0-1$ $x=8$
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