College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 15

Answer

$x=-6$

Work Step by Step

Square both sides and put all terms on one side to create a quadratic equation. Then use trial and error to factor it, and set the values found equal to zero. $\sqrt {2x+13}=x+7$ $(\sqrt {2x+13})^2=(x+7)^2$ $2x+13=x^2+14x+49$ $x^2+12x+36=0$ $(x+6)(x+6)=0$ $x=-6$
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