College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 178: 14



Work Step by Step

Square both sides and put all terms on one side to create a quadratic equation. Then use trial and error to factor it, and set the values found equal to zero. One of the solutions does not work. $\sqrt {x+10}=x-2$ $(\sqrt {x+10})^2=(x-2)^2$ $x+10=x^2-4x+4$ $x^2-5x-6=0$ $(x+1)(x-6)=0$ $x=-1,6$ $\sqrt {-1+10}\ne-1-2$ $x=6$
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