## College Algebra (6th Edition)

$x=6$
Square both sides and put all terms on one side to create a quadratic equation. Then use trial and error to factor it, and set the values found equal to zero. One of the solutions does not work. $\sqrt {x+10}=x-2$ $(\sqrt {x+10})^2=(x-2)^2$ $x+10=x^2-4x+4$ $x^2-5x-6=0$ $(x+1)(x-6)=0$ $x=-1,6$ $\sqrt {-1+10}\ne-1-2$ $x=6$