## College Algebra (10th Edition)

The solution is $[-1,2]$
$-|2x-1|\geq -3$ Isolate absolute value. $|2x-1|\leq 3$ Solve absolute value. $-3\leq2x-1\leq 3$ Solve the compound inequality. $-3+1\leq2x-1+1\leq 3+1$ Add 1 to each term. $-2\leq2x\leq 4$ $\frac{-2}{2}\leq\frac{2x}{2}\leq\frac{4}{2}$ Divide each term by 2. $-1\leq{x}\leq2$ The solution set is {$x| -1\leq{x}\leq2$}.