Answer
$(-\infty,1/3)\cup(1,\infty)$
Work Step by Step
$|2-3x|\gt1$, so $2-3x\gt1$ or $2-3x\lt-1$,
so $-3x\gt-1$ or $-3x\lt-3$,
so $x\lt1/3$ or $x\gt1$thus the solution set is $(-\infty,1/3)\cup(1,\infty)$
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