College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 133: 20


The solution set is { $-12,12$}.

Work Step by Step

$\frac{3}{4}|x|=9$ Isolate the absolute value by making the coefficient of$ |x|$ one. $|x|=9\cdot\frac{4}{3}$ $|x|=12$ $x=12$ or $x=-12$ The solution set is { $-12,12$}.
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