College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding: 31

Answer

The real solution set is {-2,-1,0,1}.

Work Step by Step

$|x^2+x-1|=1$ $x^2+x-1=1$ or $x^2+x-1=-1$ $x^2+x-1-1=0$ or $x^2+x+1-1=0$ $x^2+x-2=0$ or $x^2+x=0$ $(x+2)(x-1)=0$ or $x(x+1)=0$ $x+2=0$ or $x-1=0$ or $x =0 $ or $x+1=0$ $x=-2 $ or $x=1$ or $x=0 $ or $x=-1$ The real solution set is {-2,-1,0,1}.
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