Answer
The solution set is {$-4,4$}.
Work Step by Step
$|x^2-16|=0$
$x^2-16=0$
$(x-4)(x+4)=0$
$x-4=0$ or $x+4=0$
$x=4$ or $x=-4$
The solution set is {$-4,4$}.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 133: 28
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