College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 133: 33


The solution set is {$\frac{8}{7},4$}.

Work Step by Step

$|\frac{3x-2}{2x-3}|=2$ $\frac{3x-2}{2x-3}=2$ or $\frac{3x-2}{2x-3}=-2$ $3x-2=2(2x-3)$ or $3x-2=-2(2x-3)$ $3x-2=4x-6$ or $3x-2=-4x+6$ $3x-4x=-6+2$ or $3x+4x=6+2$ $-x=-4$ or $7x=8$ $x=4$ or $x=\frac{8}{7}$ The solution set is {$\frac{8}{7},4$}.
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