College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding: 19


The solution set is{ $-\frac{27}{2},\frac{27}{2}$}.

Work Step by Step

$\frac{2}{3}|x|=9$ Isolate the absolute value by making the coefficient of$ |x|$ one. $|x|=9\cdot\frac{3}{2}$ $|x|=\frac{27}{2}$ $x=\frac{27}{2}$ or $x=-\frac{27}{2}$ The solution set is{ $-\frac{27}{2},\frac{27}{2}$}.
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