College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding: 27


The solution set is {$-3,3$}.

Work Step by Step

$|x^2-9|=0$ $x^2-9=0$ $(x-3)(x+3)=0$ $x-3=0$ or $x+3=0$ $x=3$ or $x=-3$ The solution set is {$-3,3$}.
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