## College Algebra (10th Edition)

The solution set is {$x|-5\lt{x}\lt5$}
$|3x|\lt15$ $-15\lt3x\lt15$ Divide each term by 3 $\frac{-15}{3}\lt\frac{3x}{3}\lt\frac{15}{3}$ $-5\lt{x}\lt5$ The Solution set is {$x|-5\lt{x}\lt5$}