Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 133: 34

The solution set is {$-3,-1$}.

$|\frac{2x+1}{3x+4}|=1$ $\frac{2x+1}{3x+4}=1$ or $\frac{2x+1}{3x+4}=-1$ $2x+1=1(3x+4)$ or $2x+1=-1(3x+4)$ $2x+1=3x+4$ or $2x+1=-3x-4$ $2x-3x=4-1$ or $2x+3x=-4-1$ $-x=3$ or $5x=-5$ $x=-3$ or $x=-1$ The solution set is {$-3,-1$}.